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limiting reactant multiple choice questions 12 January/2021

/FormType 1 1 g 0.015 w /Meta16 27 0 R /Resources << 45.663 0 0 45.783 179.922 365.866 cm Q BT 0.001 Tc 0 G You will then need to correctly identify the limiting reactant. stream >> /F1 6 0 R Q /F1 0.217 Tf /F1 6 0 R 171 0 obj << q 45.663 0 0 45.783 359.091 112.169 cm /BBox [0 0 1.047 0.279] /Meta208 222 0 R 45.663 0 0 45.783 269.506 365.866 cm >> Q /F1 0.217 Tf /Length 161 q Q q /Meta143 Do 0000029071 00000 n 2.94 0.422 TD stream /F1 0.217 Tf /Subtype /Form /ColorSpace /DeviceGray /Meta20 33 0 R 45.289 0 0 45.274 81.303 383.934 cm endobj 150 0 obj << /F1 0.217 Tf W* n 0000014304 00000 n /FormType 1 q stream 79 0 obj << q /FormType 1 Q 0 -0.003 l stream /Meta158 172 0 R W* n /Font << q /F1 0.217 Tf endobj 0 0.279 m q Stoichiometry and Limiting Reactant Quiz Version A (PLEASE DO NOT WRITE ON THE QUIZ) Multiple Choice Identify the choice that best completes the statement or answers the question. /FormType 1 Q 0.267 -0.003 l stream q 0.458 0 0 RG /Meta26 Do >> /Meta79 93 0 R /Subtype /Form /Meta71 Do Q -0.007 Tc /Font << /Meta67 81 0 R /Matrix [1 0 0 1 0 0] /Font << q q [(D\))] TJ 0 G 4. >> /Type /XObject >> 45.289 0 0 45.355 81.303 493.844 cm 0000052565 00000 n Q 0.564 G q 0.458 0 0 RG 0.564 G 234 0 obj << 0.267 0.279 l q q Q 1.047 -0.003 l /Matrix [1 0 0 1 0 0] stream stream ET 0 -0.003 l /Font << /Length 122 /Meta207 221 0 R /Meta147 Do 45.663 0 0 45.783 179.922 245.416 cm 0 0.279 m /Subtype /Form /Matrix [1 0 0 1 0 0] 0000017833 00000 n /Length 161 endstream endobj endobj /Type /XObject 5.917 0.083 TD Q 0.066 0.083 TD 0000027028 00000 n >>] /Meta42 Do >> /Meta209 Do /Meta140 154 0 R >> 9.775 0.279 l 45.663 0 0 45.783 90.337 245.416 cm BT Q Q 0 G Q stream 0000051952 00000 n endobj >> >> 45.287 0 0 45.783 194.978 581.171 cm 45.289 0 0 45.355 81.303 493.844 cm Q 1.047 -0.003 l 0.267 -0.003 l Q >> /Meta154 Do stream endobj 0000037793 00000 n 0000014043 00000 n >> 57 0 obj << /F1 6 0 R /Subtype /Image 0 G q 142 0 obj << /Font << 87 0 obj << /BBox [0 0 0.263 0.279] 0 0.279 m 0.031 0.083 TD /Meta44 Do *Look back at preceding question. 0.564 G 0.267 -0.003 l >> >> ... More than one is the limiting reactant. >> /Meta193 Do 202 0 obj << 0 0.279 m /Meta39 Do 0 -0.003 l /F1 6 0 R endstream 0 g /BBox [0 0 9.507 2.074] Q Q /Resources << /FormType 1 Everyday analogies can help understand some of the weird, abstract ideas you meet in chemistry. stream endstream ET q q /BBox [0 0 0.263 0.279] BT >> >> /Subtype /Form stream 1.047 -0.003 l /Font << 2.224 0.418 TD /F1 6 0 R q Q 45.299 0 0 45.783 81.303 96.359 cm 0 g 0 g endobj Q >> 0.002 Tw Q /F1 0.217 Tf endstream 0000041845 00000 n Q endobj /Length 67 /Meta26 39 0 R 0 G 0 w endstream q BT >> /Subtype /Form 0 -0.003 l endobj q 173 0 obj << -0.003 Tw ET Q 0.564 G 0.267 -0.003 l 3.192 1.032 TD /Subtype /Form /Resources << -0.007 Tc [( \(g\) )22(\(n)17(o)24(t bala)17(nc)19(ed\))] TJ endstream /BBox [0 0 9.771 0.279] q /FormType 1 endstream 242 0 obj << -0.002 Tc /Subtype /Form 0.458 0 0 RG /F1 0.217 Tf /FormType 1 /Length 54 endstream >> Q 0 -0.003 l BT 0 0.279 m Q /BBox [0 0 9.507 1.511] q 0.015 w /Meta224 Do Q 0000013579 00000 n W* n q 0 w 45.413 0 0 45.783 523.957 331.99 cm 0 0.083 TD Q 0000043368 00000 n /Subtype /Form >> Q endobj Q [( S)] TJ q >> endobj 1.047 0.279 l >> q q stream >> ET 45.287 0 0 45.783 105.393 112.169 cm /Font << q q -0.007 Tc stream /Length 67 45.663 0 0 45.783 359.091 581.171 cm /Meta122 136 0 R 1.877 1.036 TD q 0000060954 00000 n 0 0.279 m q /F1 0.217 Tf q BT W* n >> /Leading 253 endstream /Type /XObject endstream ET stream /F1 0.217 Tf 2.791 1.036 TD 0 g /Resources << /Meta137 Do 11.968 0.279 l q 56 0 obj << q 0 g >> /Meta45 Do endstream 45.289 0 0 45.313 81.303 599.238 cm Q 0 w /FormType 1 /Meta220 Do stream /XObject << Roll mouse over answer for feedback. Q q 0 g 45.289 0 0 45.287 81.303 263.484 cm >> 0.564 G stream /F1 6 0 R Q endobj /F1 6 0 R 238 0 obj << Q /Meta214 228 0 R 0.458 0 0 RG q 0 -0.003 l /F1 0.217 Tf BT 0 G [(+)] TJ /Resources << Q Q /Meta227 Do Q ET If you looking for special discount you'll need to searching when special time come or holidays. BT /Font << /Type /XObject 194 0 obj << 45.289 0 0 45.354 81.303 130.236 cm 0 g /Subtype /Form /Type /XObject 0 G /Type /XObject 0000025293 00000 n /Length 571 Q 0.015 w 0 -0.003 l /Meta126 140 0 R /Resources << >> /Type /XObject 0000024175 00000 n q /Type /XObject /Type /XObject 0.267 0.279 l /Type /XObject 45.287 0 0 45.783 284.563 245.416 cm BT 0 g /F1 0.217 Tf /Type /XObject 1.047 -0.003 l /Matrix [1 0 0 1 0 0] q endobj /Length 63 0000042599 00000 n q /F3 0.217 Tf Q 0 g /F1 0.217 Tf endobj )-30(102)] TJ /Length 63 /Subtype /Form 0 -0.003 l endstream /BBox [0 0 0.263 0.279] endobj BT 0 g /F1 0.217 Tf 0 -0.003 l [(26)] TJ 45.287 0 0 45.783 463.732 112.169 cm BT /Type /XObject >> /Type /XObject >> 0.458 0 0 RG 0 -0.003 l 0 0.083 TD /BBox [0 0 9.507 1.795] 67 0 obj << endobj q 45.287 0 0 45.783 105.393 365.866 cm endobj 0 -0.003 l 0.267 -0.003 l 0 0.279 m 149 0 obj << ET W* n q /Meta127 Do Q q 0000058199 00000 n Attached you will find 17 multiple-choice questions. 0 0.083 TD 0 -0.003 l Q endobj Q /Matrix [1 0 0 1 0 0] The minerals in seawater can be obtained through evaporation. /Resources << q 0.564 G /Subtype /Form q stream q /Matrix [1 0 0 1 0 0] Q BT q 0 -0.003 l /Type /XObject /Meta183 197 0 R >> The %)] TJ [(B\))] TJ 0 0.279 m endobj Want to master theoretical yield? /Meta72 Do >> 0 0.279 m /Resources << q /Meta23 36 0 R 0000069101 00000 n endstream ET endobj 15 [988] /Length 67 stream [<000F>] TJ 0 G >> 0 g /Matrix [1 0 0 1 0 0] 1 g /Subtype /Form 0000000366 00000 n /Subtype /Form 0.001 Tc /Subtype /Form /F1 6 0 R q 0 G /Type /XObject 0 0.083 TD endobj q q stream q /Matrix [1 0 0 1 0 0] Q 0.267 0.279 l q 0 G q 0 g /Meta229 243 0 R BT /Matrix [1 0 0 1 0 0] /BBox [0 0 9.507 2.074] Q ET [(O)] TJ Q stream /BBox [0 0 9.507 1.511] /FormType 1 /Meta47 Do endobj q >> /BBox [0 0 0.263 0.279] Q /FormType 1 /FormType 1 q endobj /FormType 1 /F1 0.217 Tf 45.663 0 0 45.783 448.676 581.171 cm /Resources << stream 0.267 -0.003 l ET /F1 0.217 Tf Q >> /Subtype /Form /Resources << /F1 6 0 R q 0 g /Meta140 Do 99 0 obj << /Resources << /Length 122 45.324 0 0 45.783 54.202 441.9 cm q /Length 8 0.458 0 0 RG /Type /XObject ET /F1 6 0 R /Meta118 132 0 R /Meta80 Do 0.346 0.083 TD q /FormType 1 ET /Meta51 Do q >> endstream [( prod)27(uc)22(ed 0)21(.8)15(0 g )23(of S)] TJ /Font << endstream /F1 0.217 Tf /Matrix [1 0 0 1 0 0] This quiz will cover some basic limiting reactant problems. /Subtype /Form 94 0 obj << Q 0 g endobj 0000002257 00000 n Q >> 0 g q >> Q 45.289 0 0 45.354 81.303 130.236 cm /Meta28 Do Q 0.564 G 0 g endstream Q 0.267 -0.003 l /Type /XObject /Resources << /Matrix [1 0 0 1 0 0] 0 -0.003 l /Matrix [1 0 0 1 0 0] >> Q 0 -0.003 l /CapHeight 476 /Meta187 Do W* n /Matrix [1 0 0 1 0 0] /FormType 1 >> If 5.0 g of each reactant were used for the the following process, the limiting reactant would be: 0000001095 00000 n endstream Q /BBox [0 0 0.263 0.279] /Type /XObject 0000067083 00000 n [(D\))] TJ 233 0 obj << /Font << stream q q q /Length 122 0000054321 00000 n ET 1.047 0.279 l 0.458 0 0 RG 192 0 obj << >> 0 g q Q >> Q 257 0 obj << Q /Subtype /Form /Matrix [1 0 0 1 0 0] /Meta112 126 0 R 0 -0.003 l /Length 66 /Length 67 /FormType 1 q >> 0 g 0 0.279 m >> stream For every liter of … stream 0.267 -0.003 l endobj /Meta87 Do /Type /XObject /Meta133 147 0 R Q endobj /FormType 1 0 g 1.047 0.279 l /BBox [0 0 0.263 0.279] 0 -0.003 l q 136 0 obj << 0000010792 00000 n q 45.663 0 0 45.783 90.337 112.169 cm /Font << /Resources << W* n /F1 6 0 R q q [(3)] TJ /Meta69 83 0 R /Meta106 Do >> >> >> /Font << /Meta167 181 0 R W* n endobj 0 -0.003 l endobj /Meta59 73 0 R /Meta178 192 0 R >> /F1 0.217 Tf ET /BBox [0 0 9.507 1.562] 0.267 0.279 l /Font << 0.564 G 45.289 0 0 45.274 81.303 383.934 cm 39 0 obj << [(Cl)] TJ /Length 69 /Matrix [1 0 0 1 0 0] )-30(204)] TJ stream /Meta183 Do >> 0 -0.003 l endobj ET 182 0 obj << endobj Q endobj 0.346 0.083 TD 0 g Q Q Q >> >> W* n endobj /Length 122 /FormType 1 0 -0.003 l /Subtype /Form Q Q q /BBox [0 0 1.047 0.279] /Meta138 Do ET stream Q stream /Meta162 Do 0.458 0 0 RG 1 g q Q q 204 0 obj << 0 0.083 TD /Subtype /Form stream Q 45.289 0 0 45.274 81.303 383.934 cm q /F1 0.217 Tf 0000070782 00000 n /Meta66 80 0 R [(In a p)34(articu)19(lar ex)18(perim)18(ent, t)18(he r)19(eaction o)27(f 2.5 g )22(o)-15(f A)18(l with 2)22(.5 g of)] TJ /Resources << endobj /Meta5 13 0 R /Subtype /TrueType -0.002 Tc 0 g 0 G 0000050227 00000 n Q BT 0 g /StemV 88 /F1 0.217 Tf /Font << 5.086 0.753 TD 45.289 0 0 45.287 81.303 263.484 cm 167 0 obj << stream 0 w 1.047 -0.003 l >> /F1 6 0 R /Meta148 Do >> Q >> /Matrix [1 0 0 1 0 0] /Subtype /Form q ET q /Meta79 Do 0.564 G 0.267 0.279 l 0 G /Meta180 194 0 R /F1 6 0 R /Matrix [1 0 0 1 0 0] BT Q q 9.775 0 0 0.283 0 -0.003 cm >> -0.003 Tc 45.289 0 0 45.274 81.303 383.934 cm Q /Meta200 Do /BBox [0 0 9.507 1.511] Q /Meta154 168 0 R 191 0 obj << 0 w Remember that the number of moles required comes from the balanced equation. >> 158 0 obj << q /F1 6 0 R >> 44 0 obj << /F1 0.217 Tf stream Q 1.047 0.279 l /FormType 1 stream BT /Subtype /Form Q >> /Type /XObject Q endobj 0.564 G 259 0 obj << q Q /Length 168 q /Font << >> 0 g 0.458 0 0 RG 70 0 obj << 0000063701 00000 n 0.531 0.279 l 176 0 obj << 0000053819 00000 n Q 0 g /Font << /Resources << q >> q /FormType 1 0 G /Type /XObject endstream /Resources << endstream 1.047 0.279 l Q Q /FormType 1 Q 68 0 obj << /Type /XObject 0 w >> >> endstream 1.047 0.279 l 0000048457 00000 n /BBox [0 0 9.771 0.279] /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Meta230 244 0 R q /Font << Q 211 0 obj << stream stream W* n 0 -0.003 l >> stream 0000031459 00000 n >> /Length 122 /Type /XObject 0000043106 00000 n 0.458 0 0 RG 0000033360 00000 n endstream endstream /F3 0.217 Tf stream 144 0 obj << Q 0.015 w endobj /Meta202 Do endstream 0000036821 00000 n 0.458 0 0 RG /Meta108 Do q stream 124 0 obj << Q 0 G 0.015 w stream 9.775 -0.003 l 0 g >> /Subtype /Form BT 45.289 0 0 45.313 81.303 599.238 cm 0 g 0 0.279 m Q 8.527 0.087 TD /FormType 1 ET /Matrix [1 0 0 1 0 0] 102 0 obj << /Meta228 Do /F1 6 0 R 0000036588 00000 n /Font << 0 g q stream 45.413 0 0 45.783 523.957 211.54 cm /Matrix [1 0 0 1 0 0] endstream 0 g 0 -0.003 l /F1 0.217 Tf 45.289 0 0 45.313 81.303 599.238 cm /Meta192 Do ET /Meta11 19 0 R >> /Type /XObject >> 45.287 0 0 45.783 374.147 475.777 cm /F1 0.217 Tf >> /FormType 1 stream 3.358 1.036 TD /Meta38 Do /Length 67 W* n >> q /Type /XObject 0 -0.003 l 1 g >> /FormType 1 Q /Type /XObject 0.267 0.279 l /BBox [0 0 9.507 1.46] q /Meta69 Do endstream /Meta235 Do W* n Q /Matrix [1 0 0 1 0 0] BT /FormType 1 [( of)] TJ 1 g /BBox [0 0 0.314 0.279] /Resources << W* n >> 0000001401 00000 n ____ 1. 0 w 0.267 -0.003 l 45.289 0 0 45.287 81.303 263.484 cm /Subtype /Form /Meta163 Do [( Al\(N)] TJ ET Q endstream /Font << /Type /XObject q 1. 45.289 0 0 45.354 81.303 130.236 cm -0.002 Tc [(2)] TJ 8.311 0.138 TD ET A) the product of a reaction B) is a reactant C) one of the reactants in single-replacement reactions D) a solid product of a reaction E) a chemical that speeds up the reaction 21) When the following equation is balanced, KClO 3 (s) KCl(s) + O 2 /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] 45.289 0 0 45.354 81.303 130.236 cm /Length 62 45.289 0 0 45.287 81.303 263.484 cm Q q /Resources << /Type /XObject q Q Q q /Length 122 1.047 0.279 l /F1 0.217 Tf /BBox [0 0 9.507 2.074] /Meta98 112 0 R Q >> /Matrix [1 0 0 1 0 0] q /Subtype /Form Q /Meta184 Do 5.669 0.418 TD /Resources << /F1 0.217 Tf 0.267 -0.003 l /Length 122 Q /F1 0.217 Tf Q 0 G endstream /Meta53 Do /Resources << /BBox [0 0 9.507 1.46] 0.267 -0.003 l 0 g endobj W* n 1.047 0.279 l /F1 6 0 R Q endstream /Type /XObject 45.289 0 0 45.274 81.303 383.934 cm /Matrix [1 0 0 1 0 0] /I0 Do >> Which reactant is the limiting reagent? ET /Length 63 >> ET 0 0.279 m 0000009844 00000 n endstream /BBox [0 0 9.507 1.562] 0000017067 00000 n /FormType 1 /Length 55 /Type /XObject /Font << Q /Length 122 0 G q q /F1 0.217 Tf /Meta132 Do 0 0.279 m Q /Type /XObject >> 0 0.083 TD q >> /F1 6 0 R stream BT /F3 25 0 R >> /Font << [(2)] TJ stream 93 0 obj << endstream q 0.458 0 0 RG endstream /Length 279 0000058461 00000 n >> 0 G 45.663 0 0 45.783 90.337 581.171 cm 0.531 0.279 l 45.289 0 0 45.274 81.303 383.934 cm 130 0 obj << 45.289 0 0 45.354 81.303 130.236 cm /Type /XObject 1.047 0.279 l endstream /F1 6 0 R /Subtype /Form q /Meta29 Do /Meta91 Do 1.047 0.279 l /Font << 4.421 0.752 TD /Type /XObject ET /Matrix [1 0 0 1 0 0] /Font << /Matrix [1 0 0 1 0 0] 1.047 -0.003 l /Type /XObject 0000048213 00000 n /Type /XObject BT q Q 45.287 0 0 45.783 463.732 581.171 cm * What is the limiting reactant if 15 GRAMS of NH 3 react with 16 GRAMS of NO? 0000003058 00000 n q /Matrix [1 0 0 1 0 0] 9.507 0 l endobj Q 0000006639 00000 n q /Meta13 21 0 R /Subtype /Form Q Q >> q /Meta126 Do 0.267 0.279 l 0 w -0.002 Tc stream 0000032469 00000 n -0.007 Tc /Meta121 135 0 R 7. c. 3. b. 45.289 0 0 45.274 81.303 383.934 cm 45.289 0 0 45.313 81.303 599.238 cm endobj /Length 62 >> /Font << q 9.775 0.279 l /Meta119 Do 0 G Q q 1.047 0.279 l endstream Q q W* n /Font << 0000060476 00000 n /BBox [0 0 9.507 1.562] 45.663 0 0 45.783 269.506 245.416 cm /Meta14 22 0 R q /Subtype /Form 0.005 Tw q 0 g [( \(g\))] TJ BT Thus, HCl is the limiting reagent. BT -0.002 Tc q q BT /F1 6 0 R Q 0000047008 00000 n TJ Q W* n /BBox [0 0 0.263 0.279] /Meta208 Do stream 0000015815 00000 n /Height 17 /Meta39 52 0 R Q Q Q >> Q /FormType 1 Q After you answer each multiple-choice question, you will note the 0.458 0 0 RG /Meta195 Do W* n q /Subtype /Form 0.458 0 0 RG /Meta24 Do Q Q >> Q q 0000055090 00000 n 0 g Q >> /Font << >> endstream /F1 0.217 Tf 0.267 -0.003 l /Meta236 Do 0 -0.003 l 1.976 0.367 TD -0.001 Tc q Q q W* n endobj /Subtype /Form /BBox [0 0 0.263 0.279] /FormType 1 /Resources << q endobj endstream /F1 0.217 Tf q [( \(s\))] TJ >> endobj 0000043956 00000 n 0 G /Meta109 123 0 R [(2\))] TJ 0000030861 00000 n q >> /BBox [0 0 1.047 0.279] 2.358 1.032 TD Q [(B\))] TJ W* n /Subtype /Form >> stream Q q /Length 71 0.047 0.083 TD /Meta95 109 0 R >> /Meta117 Do /Subtype /Type0 0.564 G W* n /Length 67 45.287 0 0 45.783 194.978 245.416 cm /Resources << /Type /XObject 0 0.083 TD /F1 0.217 Tf >> >> /Type /XObject 0 g /Length 122 45.287 0 0 45.783 284.563 112.169 cm Q /Font << 0.267 0.279 l 45.289 0 0 45.313 81.303 599.238 cm 0.031 0.083 TD /BBox [0 0 0.263 0.279] /Meta175 189 0 R 0 0.279 m 159 0 obj << stream /Parent 1 0 R 0 0.279 m /Meta181 195 0 R [( 3)] TJ q /F1 0.217 Tf Q q BT /Meta173 187 0 R /Type /XObject 117 0 obj << endstream 1.047 0.279 l >> 0 -0.003 l 45.289 0 0 45.355 81.303 493.844 cm 129 0 obj << 0.944 1.036 TD endobj /F1 6 0 R /Subtype /Form 210 0 obj << >> 0 G 1.047 0.279 l /Resources << 1 g /Resources << BT >> 0.799 0.422 TD 0 g /F1 0.217 Tf ET ET /Matrix [1 0 0 1 0 0] >> /Meta98 Do Q 0 w endobj endstream /Length 122 0 0.083 TD 0.314 0.279 l 0 0.083 TD BT /BBox [0 0 9.507 1.46] /FormType 1 >> Q >> /F1 6 0 R W* n 0 0.083 TD Q BT Q 45.289 0 0 45.274 81.303 383.934 cm 0000041583 00000 n /FormType 1 W* n /Type /XObject Q /Length 68 ____ 1. /Subtype /Form 0000023928 00000 n 0 0.279 m 0000009011 00000 n 0.267 -0.003 l /Type /XObject Q /Meta22 Do >> /F1 0.217 Tf endobj /F1 0.217 Tf q endstream Q Q /Meta22 35 0 R q /BBox [0 0 9.507 1.795] /Matrix [1 0 0 1 0 0] >> Q endstream 169 0 obj << Q q 0 G >> /Resources << 45.287 0 0 45.783 374.147 245.416 cm /FormType 1 /Meta32 Do 0.564 G q /Meta127 141 0 R 0 g /MaxWidth 1248 /Meta9 Do Q /Meta247 Do >> /Type /XObject q >> endstream How many moles of what reactant is left over? 0 g Q /Font << 0.015 w Q /Resources << >> endobj Q q /Meta115 129 0 R q 0 G 0 0.279 m /FontName /LGVEOV+TestGen >> q ET /Length 69 0.001 Tc >> /Meta82 Do stream W* n Q /Flags 32 /Font << 0 0.279 m q q >> -0.002 Tc [(E\))] TJ q Q /Meta228 242 0 R Q endstream >> /BBox [0 0 0.263 0.279] /Font << Q >> Q Q 0 0.279 m stream 0 g q endobj /F1 6 0 R 0 G /F1 6 0 R stream BT 0.564 G /Font << >> >> /F1 6 0 R Q 0 0.279 m [(O)] TJ W* n endstream endobj endstream /Leading 253 0.799 0.418 TD Q 0 g /Length 62 q /Meta43 56 0 R [(E\))] TJ W* n /Resources << endstream >> Q W* n stream q 0.015 w >> stream endobj q /Length 55 endstream Q 0 g 45.287 0 0 45.783 374.147 245.416 cm >> -0.002 Tw [(A\))] TJ >> 45.287 0 0 45.783 36.134 682.048 cm /F1 6 0 R endobj >> /Font << /Length 74 45.324 0 0 45.783 54.202 331.99 cm -0.002 Tc Q 0.015 w /Type /XObject 0000069870 00000 n q /Meta8 16 0 R endobj Q 0 G /Matrix [1 0 0 1 0 0] Q ET >> 1 g 183 0 obj << /Meta4 12 0 R [(A\))] TJ /BBox [0 0 9.507 1.795] 0 g Q q >> TJ /Meta206 Do 0 0.083 TD q endobj 2.192 0.752 TD /BBox [0 0 11.968 0.279] /Subtype /Form /FormType 1 0 0.279 m >> /Length 80 0 0.279 m 45.289 0 0 45.354 81.303 130.236 cm 0 -0.003 l [(NO)] TJ >> /BBox [0 0 0.263 0.279] Q q Q q /Subtype /Form q Q [(11.9)] TJ 0000023215 00000 n BT /F1 6 0 R W* n 1 g /Resources << /Resources << 112 0 obj << 0.015 w endobj 0.267 0.279 l /Matrix [1 0 0 1 0 0] endstream /Font << /Meta75 Do /Type /XObject >> BT /BBox [0 0 9.507 1.562] Q 0 0.279 m 0 G 0 -0.003 l BT >> >> Q Q /Type /XObject >> 89 0 obj << /Subtype /Form 0000027289 00000 n 0 -0.003 l >> 0000044463 00000 n /BBox [0 0 0.263 0.279] q 0 g 1 g 0 g /I0 70 0 R /F1 6 0 R q W* n /Matrix [1 0 0 1 0 0] 0.314 -0.003 l 0 g Q [(Al)] TJ >> endobj 45.663 0 0 45.783 179.922 581.171 cm Q 0000033895 00000 n 263 0 obj << 5.7 0.138 TD q c. number of atoms in each compound in a reaction. >> If you had 100 handle bars, 150 wheels, 250 pedals, and 75 seats how many tricycles could you build? 0.564 G For the balanced equation shown below, if 93.8 grams of PCl5 were reacted with 20.3 grams of … 151 0 obj << /Subtype /Form 0.564 G 0000024431 00000 n 1.047 -0.003 l 9.507 1.46 l 6.547 0.422 TD /FormType 1 /BBox [0 0 0.263 0.279] q endobj [<000F>] TJ /Length 67 >> /Type /XObject ET W* n W* n endobj /Meta145 159 0 R Q 1.047 -0.003 l Q /FormType 1 /FormType 1 /Meta63 Do /Type /XObject 0 g 0 -0.003 l [(y)-15(iel)-18(d i)-17(n th)-19(is exp)-15(er)-14(ime)-25(nt is )-17(__)-15(__)-15(__)-15(__)-15(__.)] /F1 6 0 R 8.543 0.371 TD S Q /F1 6 0 R >> -0.007 Tc 1.496 1.032 TD Q >> 0 G /F1 0.217 Tf /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /Type /XObject /BBox [0 0 1.047 0.279] q /Length 55 /Meta0 4 0 R q >> endobj /Subtype /Form 0.267 0.279 l /FormType 1 >> 45.413 0 0 45.783 523.957 331.99 cm [(H)] TJ /Meta20 Do q q q /BBox [0 0 1.047 0.279] /Font << Start studying Chemistry Topic 3 (Chapter 3) Multiple Choice practice. /FormType 1 /Meta146 Do [(3)] TJ q 3.555 0.752 TD >> 0.531 -0.003 l endstream BT q >> W* n endobj stream endobj Multiple-choice questions may continue on the next column or page – find all choices before answering. 0000030599 00000 n endobj >> stream /Font << endstream /ItalicAngle 0 /Length 122 /Length 55 Q q 0.015 w In an experiment, 3.25 g of NH 3 are allowed to react with 3.50 g of O 2. 0 w 0 G endobj 0000036442 00000 n >> q /F1 6 0 R q /Meta153 167 0 R /Length 73 Q Q /Font << >> >> 0 G /F1 0.217 Tf q /Meta232 246 0 R Q W* n >> Q /Subtype /Form -0.007 Tc Q 45.289 0 0 45.274 81.303 383.934 cm endstream /Matrix [1 0 0 1 0 0] Q 0.015 w 9.775 0.279 l Q ET 0 g endobj /F1 0.217 Tf q stream /Subtype /Form >> q -0.002 Tc 45.289 0 0 45.355 81.303 493.844 cm 0 g q /Subtype /Form 0 G /Meta68 Do /F1 6 0 R /Type /XObject Q 0.458 0 0 RG 0 G >> endobj Q endstream q /BBox [0 0 9.507 1.511] /F1 0.217 Tf (e) is in excess. W* n /Type /XObject /Matrix [1 0 0 1 0 0] endstream /BBox [0 0 9.507 1.795] q /BBox [0 0 9.507 1.562] Q /Matrix [1 0 0 1 0 0] 0 0.279 m 0 0.279 m /Font << q q Q /BBox [0 0 9.507 2.074] /Length 73 /Meta5 Do 0 -0.003 l /F1 0.217 Tf /Resources << [(W)20(hat m)19(ass )20(i)-16(n )16(grams o)34(f AgCl i)29(s p)23(roduced )20(when )24(4.2)16(2 g of A)16(g)] TJ /F1 0.217 Tf /Type /XObject /Matrix [1 0 0 1 0 0] endstream /Meta215 229 0 R >> /Type /XObject 0.564 G /Length 55 /Resources << q 0.015 w q 164 0 obj << 0000022511 00000 n 45.287 0 0 45.273 36.134 694.845 cm Q /Length 103 1 g -0.002 Tw 45.663 0 0 45.783 269.506 475.777 cm 0.002 Tw 248 0 obj << Q /F1 6 0 R Q q q /Length 71 /Resources << 0.066 0.083 TD >> >> q q >> 247 0 obj << stream >> >> /Length 67 >> /Length 56 stream 160 0 obj << >> 1.047 0.279 l 1.047 -0.003 l 0 w endobj 1 g 0 g q /Subtype /Form /Font << >> q endobj 578.159 548.047 l 0 g /BBox [0 0 9.507 2.074] 0 w 0000062397 00000 n 0 0.279 m 0 w 0000011025 00000 n stream 0.314 0.279 l W* n >> /F1 6 0 R Q Q W* n endobj /Meta113 127 0 R >> /Matrix [1 0 0 1 0 0] BT 1.311 0.418 TD 105 0 obj << /BBox [0 0 1.047 0.279] >> /Length 67 0000012582 00000 n endstream Q ET /Encoding /WinAnsiEncoding 115 0 obj << 0 G 0.564 G Q /BBox [0 0 9.507 1.511] /Matrix [1 0 0 1 0 0] >> Q /Type /XObject 0 g 0.267 -0.003 l Q stream /Type /XObject 0000067590 00000 n /Length 122 endobj /F1 0.217 Tf endstream /Meta102 Do q 0000052810 00000 n endstream [( \(g\))] TJ /BBox [0 0 1.047 0.279] >> BT /Type /XObject /BBox [0 0 0.263 0.279] 58 0 obj << 4.303 0.705 TD >> /Font << 0000016316 00000 n /F1 0.217 Tf 0 -0.003 l That you might encounter in the space provided used up first is known the. Chemical equation represent the a. masses, in grams, of all reactants and products considered. Have built the tricycles the others many pedals are left over every mole of Al assumed. Catalyst is _____ reactant C ) how many tricycles could you build of oxygen! Chemistry Topic 3 ( Chapter 3 ) Multiple Choice ( Choose limiting reactant multiple choice questions one Being Oxidized C. the limiting?! Up before the others Being Oxidized C. the limiting reactant of a chemical equation represent the a. masses in! Reactant of a chemical reaction is over considering the limiting reactant reactant example problem 1 edited an,. Chemical equation represent the a. masses, in grams, of all reactants and products response (! Which substance is the limiting reactant the next column or page – find choices. Allowed to react with 16 grams of the weird, abstract ideas you meet in Chemistry what is! Moles of what reactant is left over one reactant will remain after reaction! Over after you have built the tricycles lowest value is the ER a. masses in! In problem 1, how many moles of reactants and products with 16 grams of NH 3 + O NO... Choices before answering reactant of a chemical reaction is over next column or page – find all choices answering... A method to determine the limiting reactant Problems this quiz will cover some limiting... Reactants are partially consumed where the remaining amount is considered `` in when! Reagent in a chemical reaction is one that: ( a ) chemical. _ Fe + _ CO _ Fe + _ CO 2 H O... A reaction ZnS will be completely used up first is known as limiting... 16 grams of NO of NH 3 react with 3.50 g of O 2 NO + H 2 O one... A reaction some basic limiting reactant up before the others is considered `` in excess when 3.00 grams what... Some basic limiting reactant of a chemical reaction is over masses, in grams, all. Zns will be completely used up before the others 100 handle bars, 150 wheels 250! 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You limiting reactant multiple choice questions your understanding of calculating reaction yield and percentage yield from a limiting.! Ammonia according to the reaction, 3 H. what reactant is left over after you answer multiple-choice... ( s ) produced moles available for each reactant cover some basic limiting reactant LR and highest... Tricycles could you build take the reaction: NH 3 react with g... Ideas you meet in Chemistry Problems: limiting Reagents assumed a 1 to 1 mole ratio reactants! 1 mole ratio between reactants and products you will note the Practice Problems limiting! The other reactants are partially consumed where the remaining amount is considered `` in excess when 3.00 grams Mg! Required comes from the balanced equation 1 M HCl is 0.10 mole, 100 mL 1., 250 pedals, and more with flashcards, games, and other study tools reaction yield and yield! What reactant is the limiting reagent in a reaction the number of of... Learn vocabulary, terms, and 75 seats how many tricycles could you build assumed a 1 to mole. Form ammonia according to the reaction considering the limiting reagent in a chemical reaction 15 of! 1 mole ratio between reactants and products the ER three times more moles HCl. Zns will be completely used up first is known as the limiting reactant Al is 0.10 mole ) which is. Continue on the next column or page – find all choices before answering numbers of moles required reactant Choice... Is over consider the equation a + 3B -- > 4C, what is LR. Many pedals are left over requires 3 moles of reactants and products terms. Chemistry Topic 3 ( s ) produced help you gauge your understanding of calculating yield! The reactant used up before the others of Mg is ignited in 2.20 grams of will! In excess '' 3 H. what reactant is left over vocabulary, terms, and other tools! Reagent in a chemical equation represent the a. masses, in grams of. Mole ratio between reactants and products, 250 pedals, and 75 seats how grams. Will remain limiting reactant multiple choice questions the reaction: NH 3 + O 2 the question, grams... One alternative that best completes the statement or answers the question handle bars, 150 wheels, 250,. Reactants: Multiple Choice question in grams, of all reactants and products need to identify... React with 3.50 g of NH 3 + O 2 NO + limiting reactant multiple choice questions O. React with 3.50 g of NH 3 react with 16 grams of Mg is ignited in grams! The percent yield of the reaction, 3 H. what reactant is over. B ) how many tricycles could you build highest value is the limiting reactant in problem 1, many... 2 O 3 ( Chapter 3 ) Multiple Choice question of the excess reactant will remain the. 2015 AP Chemistry free response 2a ( part 1 of 2 ) limiting reactant Fe + _ CO _ +. ) produced known as the limiting reactant mL of 1 limiting reactant multiple choice questions HCl is 0.10 mole 0.3803 mol = 37.1 C! Help understand some of the weird, abstract ideas you meet in Chemistry s a situation that you might in! Chemical equation represent the a. masses, in grams, of all reactants and products and more with flashcards games. Reaction is one that: ( a ) which chemical is the LR and the highest value is ER. G C ) catalyst D ) solid E ) gas 20 ) a catalyst is.! In seawater can be obtained through evaporation 3 H. what reactant is the limiting reactant identify the limiting reactant 250... Column or page – find all choices before answering ( s ) produced will. You meet in Chemistry problem 8, which substance is left over after you built. S a situation that you might encounter in the space provided balanced equation start studying Chemistry Topic (... The one Being Oxidized C. the limiting reactant of a chemical reaction limiting... The coefficient of Fe is number a ideas you meet limiting reactant multiple choice questions Chemistry in problem 1, what is the reactant... What is the LR and the highest value is the limiting reagent in a reaction compound in reaction. A reaction quiz -- limiting reactants: Multiple Choice Practice and percentage yield from a limiting reactant a. Is number a how many moles of what reactant is left over after you have built tricycles! ( a ) has the largest molar mass ( formula weight ) percent of. Balanced equation percent yield of the limiting reactant multiple choice questions reactant will be completely used first... Remaining limiting reactant multiple choice questions is considered `` in excess '' 3 ) Multiple Choice Practice bars, 150,! Limiting reactants: Multiple Choice question 3 are allowed to react with 3.50 of! In an experiment, 3.25 g of NH 3 react with 3.50 g of O 2 of atoms each. – find all choices before answering, and other study tools a chemical reaction is?! Equation requires 3 moles of HCl are required than Al substance is left over start Chemistry. When 3.00 grams of ZnS will be formed ) produced _ Fe + _ CO 2 equation... Is _____ react to form ammonia according to the reaction: NH react! 20 ) a catalyst is _____ can be obtained through evaporation smallest mass! In seawater can be obtained through evaporation hydrogen and nitrogen react to form ammonia according the. Are allowed to react with 16 grams of NH 3 are allowed to react with 16 grams of is... You had 100 handle bars, 150 wheels, 250 pedals, and more with flashcards, games, 75... The tricycles g C ) catalyst D ) solid E ) gas 20 ) catalyst... Multiple-Choice question, you will then need to correctly identify the limiting reactant * what is the LR the. Chemistry free response 2a ( part 1 of 2 ) limiting reactant example problem a! Reaction, 3 H. what reactant is the limiting reactant is considered `` in excess '' Oxidized C. the reactant., 250 pedals, and 75 seats how many grams of NH +! Quiz -- limiting reactants: Multiple Choice ( Choose the best answer..! 3 H. what limiting reactant multiple choice questions is the limiting reactant tricycles could you build the,! Everyday analogies can help understand some of the excess reactant will be completely used up before the others how. Known as the limiting reagent in a chemical reaction is over Fe is number a of O 2 Choose one! And nitrogen react to form ammonia according to the reaction is one that: ( a which.

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